**Match Column I with Column II (Nature of reaction):**
**Column I:**
(A)
(B)
(C)
(D)
**Column II:**
(p) Disproportionation
(q) Comproportionation
(r) Redo

Question

**Match Column I with Column II (Nature of reaction):**
**Column I:**
(A) $2H_2O_2 \rightarrow 2H_2O + O_2$
(B) $Ag^{2+} + Ag \rightarrow 2Ag^+$
(C) $PbO_2 + H_2O_2 \rightarrow PbO + H_2O + O_2$
(D) $BaO_2 + H_2SO_4 \rightarrow BaSO_4 + H_2O_2$
**Column II:**
(p) Disproportionation
(q) Comproportionation
(r) Redox reaction
(s) Non-redox reaction

Prashant Kotian · Accepted Answer

Correct answer: A. **Logic:**
(A) Oxygen (-1) goes to -2 and 0 (Disproportionation).
(B) (+2) and (0) both go to +1 (Comproportionation).
(C) (+4 +2) and (-1 0) is a standard redox reaction ( is reducing agent).
(D) Double displacement with no change in O.S. (peroxide remains peroxide).

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