**Match Column I with Column II (Oxidation state of underlined element):** <br> **Column I:** <br> ( — Redox Reactions and Volumetric Analysis Chemistry Question
Question
**Match Column I with Column II (Oxidation state of underlined element):** <br> **Column I:** <br> (A) $\underline{Cr}O_5$ <br> (B) $H_2\underline{S}_2O_8$ <br> (C) $\underline{P}H_3$ <br> (D) $Na_2\underline{S}_2O_3$ <br> **Column II:** <br> (p) +2 <br> (q) +6 <br> (r) -3 <br> (s) +6
Answer: A
💡 Solution & Explanation
**Logic:** <br> (A) $CrO_5$ has a butterfly structure with 4 peroxide oxygens (-1) and 1 oxo oxygen (-2). $Cr$ is +6. <br> (B) $H_2S_2O_8$ has one peroxide linkage. $S$ is in +6. <br> (C) In $PH_3$, Hydrogen is +1, so $P$ is -3. <br> (D) In $Na_2S_2O_3$, average O.S. of $S$ is +2 ($2x + 3(-2) = -2$).
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