In , the oxidation state of and are: | Redox Reactions and Volumetric Analysis — Chem-Mantra

Redox Reactions and Volumetric AnalysiseasyMCQ SINGLE

Question

In $K_4[Fe(CN)_6]$, the oxidation state of $C$ and $N$ are:

Answer: A

💡 Solution & Explanation

In the $CN^-$ ligand, carbon is $+2$ and nitrogen is $-3$ ($x + y = -1$; $C$ is less electronegative than $N$). [1]

💬

Still have doubts about this question?

Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry