In the reaction , the number of moles of oxidized by 1 mole of is: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
In the reaction $Cr_2O_7^{2-} + Fe^{2+} + H^+ \rightarrow Cr^{3+} + Fe^{3+} + H_2O$, the number of moles of $Fe^{2+}$ oxidized by 1 mole of $Cr_2O_7^{2-}$ is:
Answer: A
💡 Solution & Explanation
$n$-factor of $Cr_2O_7^{2-}$ is 6 ($2 \times (6-3)$). $n$-factor of $Fe^{2+}$ is 1. <br>Equivalents of $Cr_2O_7^{2-}$ = Equivalents of $Fe^{2+}$. <br>$1 \times 6 = (\text{moles } Fe^{2+}) \times 1$. Moles = 6. [1]
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