Oxidation number of in is: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
Oxidation number of $S$ in $Na_2S_2O_3$ is:
Answer: A
💡 Solution & Explanation
Calculation: $2(+1) + 2x + 3(-2) = 0 \Rightarrow 2x = 4 \Rightarrow x = +2$. [1]
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