mL of solution is required to oxidize mL of oxalic acid solution in acidic medium. The molarity of o — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

Meq $KMnO_4 = 100 \times 0.02 \times 5 = 10$. <br>Meq oxalic acid ($H_2C_2O_4$, $n=2$) = $20 \times M \times 2 = 40M$. <br>$40M = 10 \Rightarrow M = 10/40 = 0.25 M$. (Wait, calculation check: $10/40 = 0.25$. Correct Answer B(0.5) in some keys often assumes a different volume, but based on these values, it is 0.25 M). [1]