In the reaction , the oxidation state of sulfur changes from: — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

In $S_2O_3^{2-}$, $2x + 3(-2) = -2 \Rightarrow 2x = 4 \Rightarrow x = +2$. <br>In $S_4O_6^{2-}$, $4x + 6(-2) = -2 \Rightarrow 4x = 10 \Rightarrow x = +2.5$. <br>The change is from +2 to +2.5. [1]