In the reaction , the oxidation state of sulfur changes from: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
In the reaction $I_2 + 2S_2O_3^{2-} \rightarrow S_4O_6^{2-} + 2I^-$, the oxidation state of sulfur changes from:
Answer: A
💡 Solution & Explanation
In $S_2O_3^{2-}$, $2x + 3(-2) = -2 \Rightarrow 2x = 4 \Rightarrow x = +2$. <br>In $S_4O_6^{2-}$, $4x + 6(-2) = -2 \Rightarrow 4x = 10 \Rightarrow x = +2.5$. <br>The change is from +2 to +2.5. [1]
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