The oxidation state of in is: | Redox Reactions and Volumetric Analysis — Chem-Mantra

Redox Reactions and Volumetric AnalysiseasyMCQ SINGLE

Question

The oxidation state of $Cr$ in $[Cr(H_2O)_4Cl_2]Cl$ is:

Answer: A

💡 Solution & Explanation

The complex is $[Cr(H_2O)_4Cl_2]^+$. <br>Calculation: $x + 4(0) + 2(-1) = +1 \Rightarrow x = +3$. [3, 11]

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