mL of is titrated with in acidic medium. The volume of required is: — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

Meq of $FeSO_4$ ($n=1$) = $50 \times 0.1 \times 1 = 5$. <br>Meq of $KMnO_4$ ($n=5$) = $V \times 0.02 \times 5 = 0.1V$. <br>$0.1V = 5 \Rightarrow V = 50$ mL. (Note: Key correction, $50 \times 0.1 / (0.02 \times 5) = 50$). [7, 8]