-factor of in the reaction is: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
$n$-factor of $S_2O_3^{2-}$ in the reaction $S_2O_3^{2-} + Cl_2 + H_2O \rightarrow SO_4^{2-} + Cl^- + H^+$ is:
Answer: A
💡 Solution & Explanation
$S$ in $S_2O_3^{2-}$ is $+2$. $S$ in $SO_4^{2-}$ is $+6$. <br>Change per $S$ atom = 4. <br>Since there are 2 $S$ atoms per molecule, total electrons lost ($n$-factor) = $2 \times 4 = 8$. [1, 2]
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