The oxidation state of the central metal atom in is: — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

In $K_3[Fe(CN)_6]$, there are 3 $K^+$ ions, so the complex ion is $[Fe(CN)_6]^{3-}$. <br>Calculation: $x + 6(-1) = -3 \Rightarrow x = +3$. [1]