mL of is required to oxidize mL of in acidic medium. The molarity of is: — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

**Step 1:** $n$-factor of $KMnO_4 = 5$. <br>**Step 2:** $n$-factor of $FeC_2O_4 = 3$ ($Fe^{2+} \rightarrow Fe^{3+}$ is 1, $C_2O_4^{2-} \rightarrow 2CO_2$ is 2). <br>**Step 3:** Eq of $KMnO_4 = 100 \times 0.01 \times 5 = 5$. <br>**Step 4:** Eq of $FeC_2O_4 = 20 \times M \times 3 = 60M$. <br>**Step 5:** $60M = 5 \Rightarrow M = 5/60 = 0.0833 M$. [1, 2]