-factor of when it is converted to is: — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

Initial O.S. of $Fe$ in $Fe_{0.9}O = 2/0.9 = 20/9$. <br>Final O.S. of $Fe$ in $Fe_2O_3 = 3$. <br>Change per $Fe$ atom = $3 - 20/9 = 7/9$. <br>Since there are $0.9$ $Fe$ atoms per formula unit: $n$-factor = $0.9 \times (7/9) = 0.7$. (Note: Key/Standard often lists 0.8 for specific stoichiometry like $Fe_{0.94}O$, but for $0.9$, it is $0.7$. Based on source logic: A).