In the reaction , phosphorus is: — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

In $P_4$, O.S. = 0. In $PH_3$, O.S. = -3 (reduction). In $NaH_2PO_2$, O.S. = +1 (oxidation). Since the same element phosphorus is both oxidized and reduced, it undergoes disproportionation.