Equivalent weight of in neutral medium is (M = molecular weight): | Redox Reactions and Volumetric Analysis — Chem-Mantra | Chem-Mantra

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Redox Reactions and Volumetric AnalysiseasyMCQ SINGLE

Question

Equivalent weight of $KMnO_4$ in neutral medium is (M = molecular weight):

Answer: C

💡 Solution & Explanation

In neutral or weakly alkaline medium, $MnO_4^-$ (+7) is reduced to $MnO_2$ (+4). <br>Change in O.S. = 3. <br>Equivalent weight = Molecular weight / 3.

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