The oxidation state of sulfur in , , and are respectively: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
The oxidation state of sulfur in $S_8$, $S_2F_2$, and $H_2S$ are respectively:
Answer: A
💡 Solution & Explanation
$S_8$ is elemental state, so O.S. = $0$. <br>$S_2F_2$: $2x + 2(-1) = 0 \Rightarrow 2x = 2 \Rightarrow x = +1$. <br>$H_2S$: $2(+1) + x = 0 \Rightarrow x = -2$.
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