When is converted into in acidic medium, the change in oxidation state of chromium is: — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

In $CrO_4^{2-}$, O.S. of $Cr$: $x + 4(-2) = -2 \Rightarrow x = +6$. <br>In $Cr_2O_7^{2-}$, O.S. of $Cr$: $2x + 7(-2) = -2 \Rightarrow 2x = 12 \Rightarrow x = +6$. <br>The oxidation state remains $+6$; hence the change is $0$.