The reaction of white phosphorus () with aqueous gives phosphine () along with another phosphorus co — Redox Reactions and Volumetric Analysis Chemistry Question
Question
The reaction of white phosphorus ($P_4$) with aqueous $NaOH$ gives phosphine ($PH_3$) along with another phosphorus containing compound. The oxidation states of phosphorus in $PH_3$ and the other product are respectively:
Answer: A
💡 Solution & Explanation
The reaction is: $P_4 + 3NaOH + 3H_2O \rightarrow PH_3 + 3NaH_2PO_2$. <br>In $PH_3$: $x + 3(+1) = 0 \Rightarrow x = -3$. <br>In $NaH_2PO_2$: $1 + 2(1) + x + 2(-2) = 0 \Rightarrow 3 + x - 4 = 0 \Rightarrow x = +1$.
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