mL of tap water containing required mL of for titration. The hardness in ppm of is: — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

Meq $Ca(HCO_3)_2$ = Meq $HCl = 10 \times 0.01 = 0.1$. <br>Meq of $CaCO_3$ equivalents = $0.1$. <br>Mass $CaCO_3 = (0.1 \times 50) / 1000 = 0.005$ g in $100$ mL. <br>In $1000$ mL ($1$ L), $0.05$ g = $50$ mg/L = $50$ ppm.