Oxidation number of in (Sodium Nitroprusside) is: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
Oxidation number of $Fe$ in $Na_2[Fe(CN)_5NO]$ (Sodium Nitroprusside) is:
Answer: B
💡 Solution & Explanation
In this complex, $NO$ is neutral (some debate, but IUPAC/JEE standard O.S. for Fe here is +2 based on $NO^+$ linkage). <br>Calculation: $2(+1) + x + 5(-1) + 1(+1) = 0 \Rightarrow 2 + x - 5 + 1 = 0 \Rightarrow x = +2$.
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