In the reaction (in acidic medium), the -factor of is: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
In the reaction $K_4[Fe(CN)_6] \rightarrow Fe^{3+} + CO_2 + NO_3^-$ (in acidic medium), the $n$-factor of $K_4[Fe(CN)_6]$ is:
Answer: C
💡 Solution & Explanation
$Fe^{2+} \rightarrow Fe^{3+}$ ($1 e^-$). <br>$6C^{2+} \rightarrow 6C^{4+}$ ($12 e^-$). <br>$6N^{3-} \rightarrow 6N^{5+}$ ($48 e^-$). <br>Total electrons lost per molecule = $1 + 12 + 48 = 61$.
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes