Equivalent weight of as a reducing agent is (M = Mol. Wt.): — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

The molecule contains 2 units of $C_2O_4$. Each $C_2O_4^{2-} \rightarrow 2CO_2$ involves 2 electrons. <br>Total electrons ($n$-factor) = $2 \times 2 = 4$. <br>Equivalent weight = M/4.