Oxidation number of in (Oleum) is: | Redox Reactions and Volumetric Analysis — Chem-Mantra

Redox Reactions and Volumetric AnalysiseasyMCQ SINGLE

Question

Oxidation number of $S$ in $H_2S_2O_7$ (Oleum) is:

Answer: A

💡 Solution & Explanation

$H_2S_2O_7$ structure: $HO-SO_2-O-SO_2-OH$. <br>Calculation: $2(+1) + 2x + 7(-2) = 0 \Rightarrow 2x = 12 \Rightarrow x = +6$.

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