The oxidation state of in and are respectively: | Redox Reactions and Volumetric Analysis — Chem-Mantra

Redox Reactions and Volumetric AnalysiseasyMCQ SINGLE

Question

The oxidation state of $Xe$ in $XeO_3$ and $XeF_6$ are respectively:

Answer: A

💡 Solution & Explanation

In $XeO_3$: $x + 3(-2) = 0 \Rightarrow x = +6$. <br>In $XeF_6$: $x + 6(-1) = 0 \Rightarrow x = +6$.

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