The oxidation state of in and are respectively: — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

In $XeO_3$: $x + 3(-2) = 0 \Rightarrow x = +6$. <br>In $XeF_6$: $x + 6(-1) = 0 \Rightarrow x = +6$.