The oxidation state of in and are respectively: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
The oxidation state of $Xe$ in $XeO_3$ and $XeF_6$ are respectively:
Answer: A
💡 Solution & Explanation
In $XeO_3$: $x + 3(-2) = 0 \Rightarrow x = +6$. <br>In $XeF_6$: $x + 6(-1) = 0 \Rightarrow x = +6$.
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