mL of oxidizes in acidic medium. The volume of evolved at STP is: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
$100$ mL of $0.01 M$ $KMnO_4$ oxidizes $H_2O_2$ in acidic medium. The volume of $O_2$ evolved at STP is:
Answer: A
💡 Solution & Explanation
Meq $KMnO_4 = 100 \times 0.01 \times 5 = 5$. <br>Meq $O_2$ evolved = $5$. <br>$n$-factor for $O_2$ ($H_2O_2 \rightarrow O_2$) is 2. <br>Moles $O_2 = 5 / (2 \times 1000) = 0.0025$. <br>Vol = $0.0025 \times 22400 = 56$ mL.
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