g of an oxalate was dissolved in water and the solution made to mL. mL of this solution required mL of for oxidation. The percentage of oxalate () in the sample is:

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Question

$0.5$ g of an oxalate was dissolved in water and the solution made to $100$ mL. $10$ mL of this solution required $8$ mL of $N/20$ $KMnO_4$ for oxidation. The percentage of oxalate ($C_2O_4^{2-}$) in the sample is:

Prashant Kotian · Accepted Answer

Correct answer: A. Meq in mL = .
Meq in mL = .
Mass of oxalate = g.
.

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