Volume of vol required to liberate mL of at STP is: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
Volume of $10$ vol $H_2O_2$ required to liberate $500$ mL of $O_2$ at STP is:
Answer: A
💡 Solution & Explanation
10 vol $H_2O_2$ means $1$ mL of $H_2O_2$ solution gives $10$ mL of $O_2$ gas. <br>To get $500$ mL of $O_2$, volume of solution = $500 / 10 = 50$ mL.
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