One mole of loses 10 moles of electrons to form a new compound . Assuming all nitrogen atoms appear — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

**Step 1:** In $N_2H_4$, O.S. of $N$ is $-2$. <br>**Step 2:** Total loss of $10e^-$ for 2 $N$ atoms = $5e^-$ lost per $N$ atom. <br>**Step 3:** New O.S. = $(\text{Initial O.S.}) + (\text{electrons lost}) = -2 + 5 = +3$.