Volume of required to neutralize mL of is: | Redox Reactions and Volumetric Analysis — Chem-Mantra

Name: JEE Advanced Chemistry
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Question

Volume of $0.1 M$ $NaOH$ required to neutralize $10$ mL of $0.1 M$ $H_2SO_4$ is:

Answer: B

💡 Solution & Explanation

meq of $H_2SO_4 = 10 \times 0.1 \times 2 = 2$. <br>meq of $NaOH = V \times 0.1 \times 1$. <br>$0.1 V = 2 \Rightarrow V = 20$ mL.

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