Oxidation state of in brown ring complex is: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
Oxidation state of $Fe$ in brown ring complex $[Fe(H_2O)_5NO]SO_4$ is:
Answer: A
💡 Solution & Explanation
In the brown ring complex, $NO$ exists as $NO^+$. <br>Calculation: $x + 5(0) + (+1) = +2$ (charge of complex ion). <br>$x + 1 = 2 \Rightarrow x = +1$. Iron is in the rare +1 oxidation state.
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