moles of is oxidized to by moles of in acidic medium. The value of is: — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

**Step 1:** $H_2SO_3 \rightarrow H_2SO_4$. O.S. of $S$ changes from $+4$ to $+6$, so $n$-factor = 2. <br>**Step 2:** $K_2Cr_2O_7 \rightarrow 2Cr^{3+}$. $n$-factor = 6. <br>**Step 3:** Equivalents of $H_2SO_3$ = $0.5 \times 2 = 1.0$. <br>**Step 4:** Equivalents of $K_2Cr_2O_7$ = $x \times 6$. <br>$6x = 1 \Rightarrow x = 1/6 \approx 0.167$.