is used to titrate mL of and mL of separately in acidic medium. The ratio of volumes of used will be — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

**Case 1:** $FeSO_4$ ($n=1$). Eq = $100 \times 0.1 \times 1 = 10$. <br>**Case 2:** $K_2C_2O_4$ ($n=2$). Eq = $100 \times 0.1 \times 2 = 20$. <br>Since $KMnO_4$ ($n=5$) is used for both, the volume required is proportional to the equivalents of the reductant. <br>Ratio $V_1 : V_2 = 10 : 20 = 1 : 2$.