A mixture of and contains nitrogen. The mass ratio of and in the mixture is: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
A mixture of $NH_4NO_3$ and $(NH_4)_2HPO_4$ contains $30.40\%$ nitrogen. The mass ratio of $NH_4NO_3$ and $(NH_4)_2HPO_4$ in the mixture is:
Answer: A
💡 Solution & Explanation
Let the mass of $NH_4NO_3$ ($M=80$) be $x$ and $(NH_4)_2HPO_4$ ($M=132$) be $y$. <br>Nitrogen in $NH_4NO_3 = (28/80)x = 0.35x$. <br>Nitrogen in $(NH_4)_2HPO_4 = (28/132)y = 0.212y$. <br>Total Nitrogen = $0.304(x+y)$. <br>$0.35x + 0.212y = 0.304x + 0.304y \Rightarrow 0.046x = 0.092y \Rightarrow x/y = 2/1$.
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