The oxidation number of in is: | Redox Reactions and Volumetric Analysis — Chem-Mantra

Redox Reactions and Volumetric AnalysiseasyMCQ SINGLE

Question

The oxidation number of $Cr$ in $K_3CrO_8$ is:

Answer: B

💡 Solution & Explanation

$K_3CrO_8$ is a tetraperoxo complex $[Cr(O_2)_4]^{3-}$. $Cr$ is $+5$ and 4 peroxo groups are each $-2$ (total $-8$). $+5 + (-8) = -3$. [1, 7]

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