The equivalent weight of for the reaction is [M = mol. wt.]: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
The equivalent weight of $Na_2S_2O_3$ for the reaction $2Na_2S_2O_3 + I_2 \rightarrow Na_2S_4O_6 + 2NaI$ is [M = mol. wt.]:
Answer: A
💡 Solution & Explanation
$n$-factor for $Na_2S_2O_3$ in this reaction is 1 ($S^{+2} \rightarrow S^{+2.5}$ per atom, 2 atoms = 1 electron). Eq. wt = M/1. [1, 6]
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