1 mol of is reduced to . The number of Faradays required is: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
1 mol of $MnO_4^-$ is reduced to $Mn^{2+}$. The number of Faradays required is:
Answer: A
💡 Solution & Explanation
$Mn$ goes from $+7$ to $+2$. Change in O.S. = 5. Electrons per mole = 5 moles. Since 1 mole $e^- = 1$ Faraday, 5 Faradays are required. [1, 6]
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