Oxidation state of sulfur in is: β Redox Reactions and Volumetric Analysis Chemistry Question
Question
Oxidation state of sulfur in $Na_2S_4O_6$ is:
Answer: A
π‘ Solution & Explanation
Calculation: $2(+1) + 4(x) + 6(-2) = 0 \Rightarrow 2 + 4x - 12 = 0 \Rightarrow 4x = 10 \Rightarrow x = +2.5$. (This is the average oxidation state). [1, 5]
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