Oxidation state of sulfur in is: | Redox Reactions and Volumetric Analysis — Chem-Mantra

Redox Reactions and Volumetric AnalysiseasyMCQ SINGLE

Question

Oxidation state of sulfur in $Na_2S_4O_6$ is:

Answer: A

💡 Solution & Explanation

Calculation: $2(+1) + 4(x) + 6(-2) = 0 \Rightarrow 2 + 4x - 12 = 0 \Rightarrow 4x = 10 \Rightarrow x = +2.5$. (This is the average oxidation state). [1, 5]

💬

Still have doubts about this question?

Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes

Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

Explore Courses →Free on YouTube

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry