Oxidation number of iron in is: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
Oxidation number of iron in $Fe_{0.94}O$ is:
Answer: A
💡 Solution & Explanation
Let average O.S. be $x$: $0.94(x) + 1(-2) = 0 \Rightarrow 0.94x = 2 \Rightarrow x = 2/0.94 = 200/94$. [1, 5]
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