Oxidation number of iron in is: | Redox Reactions and Volumetric Analysis — Chem-Mantra

Redox Reactions and Volumetric AnalysiseasyMCQ SINGLE

Question

Oxidation number of iron in $Fe_{0.94}O$ is:

Answer: A

💡 Solution & Explanation

Let average O.S. be $x$: $0.94(x) + 1(-2) = 0 \Rightarrow 0.94x = 2 \Rightarrow x = 2/0.94 = 200/94$. [1, 5]

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