In the reaction , which is the reducing agent? — Redox Reactions and Volumetric Analysis Chemistry Question
Question
In the reaction $Cr_2O_7^{2-} + 14H^+ + 6I^- \rightarrow 2Cr^{3+} + 3I_2 + 7H_2O$, which is the reducing agent?
Answer: C
💡 Solution & Explanation
$I^-$ is oxidized to $I_2$ (O.S. increases from $-1$ to $0$). The species that undergoes oxidation is the reducing agent. [1, 5]
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes