mL of is needed for complete oxidation of g in acidic medium. The product is . Then is: — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

$n$-factor for $N_2H_4 \rightarrow N_2$ is 4 ($2 \times (0 - (-2))$). Moles $N_2H_4 = 0.678 / 32 = 0.02118$. Eq = $0.02118 \times 4 = 0.0847$. For $K_2Cr_2O_7$ ($n=6$): $0.1 \times 6 \times V/1000 = 0.0847 \Rightarrow V = 141.25$ mL. [1, 4]