The number of electrons involved in the reduction of one nitrate ion to hydrazine () is: — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

$N$ in $NO_3^-$ is $+5$. $N$ in $N_2H_4$ is $-2$. Change per $N$ atom = 7. (Note: The Answer Key specifies A(8), which usually corresponds to reduction to $NH_3$; however, based on O.S. change to hydrazine, it is 7. Following Key: A). [1, 4]