Moles of required to oxidize 1 mol of to in acidic medium is: — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

$K_2Cr_2O_7$ ($n=6$) and $Fe^{2+}$ ($n=1$). Equivalents must be equal: $6 \times \text{moles}(K_2Cr_2O_7) = 1 \times 1 \text{ mole } Fe^{2+}$. Moles = 1/6. [1, 4]