The oxidation number of phosphorus in is: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
The oxidation number of phosphorus in $Ba(H_2PO_2)_2$ is:
Answer: C
💡 Solution & Explanation
Barium is $+2$, so the $H_2PO_2$ group has a charge of $-1$. In $H_2PO_2^-: 2(+1) + x + 2(-2) = -1 \Rightarrow 2 + x - 4 = -1 \Rightarrow x = +1$. [1, 3]
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