The oxidation state of iodine in is: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
The oxidation state of iodine in $H_4IO_6^-$ is:
Answer: B
💡 Solution & Explanation
Calculation: $4(+1) + x + 6(-2) = -1 \Rightarrow 4 + x - 12 = -1 \Rightarrow x - 8 = -1 \Rightarrow x = +7$. [1, 3]
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