-factor of in acidic medium is: — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

One molecule of $Ba(MnO_4)_2$ yields 2 $MnO_4^-$ ions. <br>In acidic medium, each $MnO_4^-$ gains $5e^-$ ($Mn^{+7} \rightarrow Mn^{+2}$). <br>Total electrons gained per molecule of $Ba(MnO_4)_2 = 2 \times 5 = 10$. Thus $n$-factor = 10. [1-34]