The oxidation state of in is: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
The oxidation state of $Cr$ in $[Cr(NH_3)_4Cl_2]^+$ is:
Answer: A
💡 Solution & Explanation
Let the oxidation state of $Cr$ be $x$. <br>$NH_3$ is a neutral ligand ($0$), $Cl$ is $-1$. <br>$x + 4(0) + 2(-1) = +1$ (net charge). <br>$x - 2 = 1 \Rightarrow x = +3$. [1-34]
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