Oxidation number of in (Marshall's acid) is: — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

$H_2S_2O_8$ contains a peroxide linkage ($-O-O-$). The structure is $HO-SO_2-O-O-SO_2-OH$. <br>Calculation: $2(+1) + 2(x) + 6(-2) + 2(-1) = 0$ (where $-1$ is for peroxide oxygens). <br>$2 + 2x - 12 - 2 = 0 \Rightarrow 2x = 12 \Rightarrow x = +6$. [1-34]