Oxidation number of iodine in , , and are respectively: — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

1. In $IO_3^-$: $x + 3(-2) = -1 \Rightarrow x = +5$. <br>2. In $IO_4^-$: $x + 4(-2) = -1 \Rightarrow x = +7$. <br>3. In $KI$: $K$ is $+1$, so $I$ must be $-1$. <br>4. In $I_2$: Elemental state, O.N. is $0$. <br>The sequence is +5, +7, -1, 0. [1-34]