-factor of in the reaction is: — Redox Reactions and Volumetric Analysis Chemistry Question
Question
$n$-factor of $CrI_3$ in the reaction $CrI_3 \rightarrow CrO_4^{2-} + IO_4^-$ is:
Answer: A,B,C
💡 Solution & Explanation
**Step 1:** $Cr^{3+} \rightarrow Cr^{6+}$ involves loss of 3 $e^-$. <br>**Step 2:** $3I^- \rightarrow 3I^{7+}$ involves loss of $3 \times 8 = 24$ $e^-$. <br>**Step 3:** Total $n$-factor = $3 + 24 = 27$. Both the components contribute to the total electron loss.
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