Which of the following is/are correct for the reaction: ? — Redox Reactions and Volumetric Analysis Chemistry Question
Question
Which of the following is/are correct for the reaction: $3S_8 + 48OH^- \rightarrow 16S^{2-} + 8S_2O_3^{2-} + 24H_2O$?
Answer: A,B,C
💡 Solution & Explanation
**(A/C)** $S$ goes from 0 to -2 and +2. This is disproportionation. <br>**(B)** In the balanced equation, 3 moles of $S_8$ (24 atoms) produce 16 $S^{2-}$ (gain $16 \times 2 = 32e^-$) and 8 $S_2O_3^{2-}$ (lose $16 \times 2 = 32e^-$). <br>Total electrons transferred = 32 per 3 moles of $S_8$. <br>Thus, $n$-factor = $32/3$.
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